Special Format Conversion in Python

The folloing string:

%2c%e3%80%90%e5%bd%a2%e3%80%91%e6%97%a0%e7%a2%8d%e7%9a%84%e3%80%82

Pass to the following function

def HexStringToString(hexString):
  # convert hex string to utf8 string
  # example: "%2c%e3%80" -> "\x2C\xE3\x80"
  bytes = []
  hexStr = ''.join( hexString.split("%") )
  for i in range(0, len(hexStr), 2):
    bytes.append( chr( int (hexStr[i:i+2], 16 ) ) )

  # decode as utf8
  string = ''.join( bytes ).decode("utf-8")

  return string

Will become

,【形】无碍的。

Pass again to the following function

def StringToHexString(string):
  # convert string to hex string
  string = string.encode('utf8')
  return ''.join( [ "%02X " % ord( x ) for x in string ] ).strip().replace(' ','%')

Will become back

2C%E3%80%90%E5%BD%A2%E3%80%91%E6%97%A0%E7%A2%8D%E7%9A%84%E3%80%82

References:

[1]	Byte to Hex and Hex to Byte String Conversion (Python recipe)

[2]	Convert bytes to a Python string